2x^2+45=20x-5

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Solution for 2x^2+45=20x-5 equation: 



2x^2+45=20x-5

We move all terms to the left:

2x^2+45-(20x-5)=0

We get rid of parentheses

2x^2-20x+5+45=0

We add all the numbers together, and all the variables

2x^2-20x+50=0

a = 2; b = -20; c = +50;
Δ = b2-4ac
Δ = -202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{4}=5$

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